YAML to C# Converter

Paste a YAML document and get C# classes with typed properties, optional JSON annotations, and namespace support.

Last updated: May 28, 2026

Root class: Namespace: Auto-propertiesPascalCase fields[JsonPropertyName]Nullable (T?)

YAML Input

Generated C# Classes

using System.Collections.Generic;
using System.Text.Json.Serialization;

public class Root
{
    [JsonPropertyName("name")]
    public string Name { get; set; }
    [JsonPropertyName("age")]
    public int Age { get; set; }
    [JsonPropertyName("active")]
    public bool Active { get; set; }
    [JsonPropertyName("address")]
    public Address Address { get; set; }
    [JsonPropertyName("tags")]
    public List<string> Tags { get; set; }
}

public class Address
{
    [JsonPropertyName("city")]
    public string City { get; set; }
    [JsonPropertyName("zip")]
    public string Zip { get; set; }
}

Client-Side Processing

Input Data Stays on Device

Instant Local Execution

Find this tool useful? Support the project to keep it free!

Buy me a coffee

What is YAML to C# Converter?

This tool converts YAML to a C# class hierarchy. It parses YAML into JSON internally, then generates C# classes that mirror the document structure. Nested mappings become nested classes, sequences become List<T>, and scalar values are typed as string, int, double, or bool.

How to Use YAML to C# Converter

Paste YAML into the input panel.

Set a root class name (optional).

Choose a namespace or leave blank.

Toggle JSON property attributes and nullable types.

Copy the generated C# code.

Common Use Cases

Generating C# models for a .NET service that deserializes YAML configs.
Typing Kubernetes or Helm values in a .NET operator.
Scaffolding model classes before writing YAML serialization code.
Converting API YAML examples to C# DTOs.

Example Input and Output

A small YAML mapping becomes a C# class.

YAML input

name: Alice
age: 30
active: true

Generated C# class

public class Root
{
    [JsonPropertyName("name")]
    public string Name { get; set; }

    [JsonPropertyName("age")]
    public int Age { get; set; }

    [JsonPropertyName("active")]
    public bool Active { get; set; }
}